I did a program to create a dictionary that contains student name, roll no and marks obtained.When I execute it to form multiple dictionaries instead of one. This is the code: def student(x,y,z):
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Secondary is S1 through S6, with students typically being able to leave at the end of S4 (when they turn 16). America K-12 ( k indergarten to 12 ) is pre-school ("kindergarten"), followed by elementary (1st to 4th grade), middle school or junior high (5th to 8th/9th grade), followed by high school (9th/10th to 12th grade).
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I have an assignment for school and one of the tasks is to display the grades that the students will be receiving. The grades are: A: 90% + B: 80% - 89% ; C: 70% - 79%; D: 60% - 69%; E: 50% - 59%; Here is some of the file, it's a comma-separated CSV file: StudentName Score Harrison 64 Jake 68 Jake 61 Hayley 86
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28. If you're using Oracle, then a feature called analytics will do the trick. It looks like this: select id, age, count(*) over (partition by age) from students; If you aren't using Oracle, then you'll need to join back to the counts: select a.id, a.age, b.age_count. from students a. join (select age, count(*) as age_count.
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Create a toString method to return the details of the student. Ask the user to enter the details of any 5 students and store them in an array. Ask the user to enter an address and print all the students who live in that address. Print all the students whose email address contains “gmail.com”. import java.util.*; public class Student{.
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select on the students table to get the possible students; a join to the marks table to match up students to marks, a join to the subjects table to resolve subject ids into names. a join to a derived table of the maximum marks in each subject. Only the students that get maximum marks will meet all three join conditions.
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3. Numbers can't be iterated over. What you're probably looking for is the range function, which will create a sequence of numbers up to the number you want: for number in range(1, students + 1): The reason I added + 1 there is because the second argument to range is exclusive. answered Feb 18, 2013 at 16:54.
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I have an assignment in my Python class. It says: Write a program that asks the user to enter a person's age. The program should display a message indicating whether the person is an infant,...
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HAVING COUNT(*) > 1. The GROUP BY clause groups the rows into groups by values in both name and email columns. Then, the COUNT () function returns the number of occurrences of each group (name,email). Then, the HAVING clause keeps only duplicate groups, which are groups that have more than one occurrence. 2.
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SHOW search_path; SET search_path TO my_schema; Check your table schema here. SELECT *. FROM information_schema.columns. For example if a table is on the default schema public both this will works ok. SELECT * FROM parroquias_region. SELECT * FROM public.parroquias_region. But sectors need specify the schema.
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